Python Practical Slips

 BCA and BBA(C.A.) Practical Slips. Python practical slips  SPPU Practical Slips. Savitribai Phule Pune University

All Python Slips Solution:

Slip  1:

A) Write a Python program to accept n number in list and remove duplicates from a list.

Slip  2:

A) Write a Python function that accepts a string and calculate the number of upper case

letters and lower case letters.

Sample String: 'The quick Brown Fox'

Expected Output:

No. of Upper case characters: 3

No. of Lower case characters: 13

def calculate(str):

  dict={"uc":0,"lc":0}

  for num in str:

     if num.isupper():

       dict["uc"]+=1

     if num.islower():

       dict["lc"]+=1

  print("No. of Upper case characters:",dict["uc"])

  print("No. of Lower case characters:",dict["lc"])

string=input("Enter String: ")

calculate(string)

OR

dict={

    "a":1,

    "b":2,

    "c":3

}

key="a"

key_value=10

if key in dict:

    dict[key]=key_value

else:

    dict[key]=key_value

print(dict)

B)Write Python GUI program to create a digital clock with Tkinter to display the time.

import tkinter as tk

import time

def update_time():

    current_time = time.strftime("%H:%M:%S")

    clock_label.config(text=current_time)

    root.after(1000, update_time) # Update the time every second

root = tk.Tk()

root.title("Digital Clock")

clock_label = tk.Label(root, font=("Arial", 48), fg="black", bg="white")

clock_label.pack()

update_time()

root.mainloop()

Slip  3:

A) Write a Python program to check if a given key already exists in a dictionary. If

key exists replace with another key/value pair. 

dict={'Name':'Mahesh','Age':20}

key=input("Enter Key to check Exist or Not: ")

if key in dict:

  print('Key Exist')

  for key in dict.keys():

    pass

  key=input('Enter key :')

  value=input('Enter Value :')

  dict[key]=value

  print(dict)

else:

  print("Key not Exists")

#You can Use Following Program Also. Following Program checks Exists or Not at the Time

of Creating Dictionary.

dict={}

n=int(input('Enter How many Keys You Want:'))

for x in range(0,n):

  key=input('Enter Key:')

  if key in dict:

      for key in dict.keys():

           pass

      key=input('The Given Key Already Exists! Add Another Key')  

  value=input('enter the value :')

  dict[key]=value

print(dict)

B)

class Student:

    def __init__(self, roll_no, name, age, gender):

        self.roll_no = roll_no

        self.name = name

        self.age = age

        self.gender = gender

class Test(Student):

    def __init__(self, roll_no, name, age, gender, marks1, marks2, marks3):

        super().__init__(roll_no, name, age, gender)

        self.marks1 = marks1

        self.marks2 = marks2

        self.marks3 = marks3

    def display_details(self):

        total_marks = self.marks1 + self.marks2 + self.marks3

        print(f"Student Details:")

        print(f"Roll No: {self.roll_no}")

        print(f"Name: {self.name}")

        print(f"Age: {self.age}")

        print(f"Gender: {self.gender}")

        print(f"Total Marks: {total_marks}")

# Create three objects of the Test class

student1 = Test(1, "Alice", 15, "Female", 80, 90, 75)

student2 = Test(2, "Bob", 16, "Male", 70, 85, 90)

student3 = Test(3, "Charlie", 14, "Male", 90, 80, 70)

# Display the details of each student

student1.display_details()

student2.display_details()

student3.display_details()

Slip  4:

A) Write Python GUI program to create background with changing colors

import tkinter as tk

import random

def change_color():

  color = "#%06x" % random.randrange(0, 0xFFFFFF)

  root.config(bg=color)

  root.after(1000, change_color)

root = tk.Tk()

root.title("Changing Background")

change_color()

root.mainloop()

.